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I want to replace the bytes. the probability may be. for example. this algorithm is here. (import) If I use this one. it won’t work.
I just use the first bytes. so I can’t know my original data. I want to find the byte of bytes. and should be able to replace.
Then I set a byte by using:
byte tmpByte = 0x78;
int tmpInt = tmpByte;
byte b = ((byte)(tmpInt >> 2));
What I actually do is:
byte tmpByte = tmpInt >> 2;
int tmpInt = tmpByte;
byte b = ((byte)(tmpInt & 0x03));
How can I improve my code?

A:

int byte0;
int byte1;
int byte2;
int byte3;

int int0;
int int1;
int int2;
int int3;

So int0 = byte0, int1 = byte1, int2 = byte2 and int3 = byte3.
Now int0 = 0x78, int1 = 0x21 and so on.
So now you only have to change the byte0, byte1, byte2 and byte3 to have the values that you need.
int byte0 = (byte)(tmpInt & 0x03);
int byte1 = (byte)((tmpInt >> 2) & 0x03);
int byte2 = (byte)((tmpInt >> 4) & 0x03);
int byte3 = (byte)((tmpInt >> 6) & 0x03);

The last line is to deal with the bytes that are in twos. A byte is 16 bits, so the low 8 bits of an int are the ones you need.

Members of the Senate Foreign Relations Committee have met with former CIA Director John Brennan and demanded answers regarding his “dishonest” testimony before the committee on Wednesday. The Democrats and Republicans demanded to know where Brennan got the information he had provided to the committee as the former director, noting the “politicized and polarizing” environment in which he made the accusations.

“I think it’s important to not only clearly delineate, but to call out, the actions and the dishonesty that John Brennan has demonstrated in this committee,” Mark Warner told reporters after the meeting with Brennan.
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